Question 2472Deck Safety70% to pass
On a vessel of 9,000 tons displacement, compute the reduction in metacentric height due to free surface in a hold having free water on the tank tops. The hold is 20 feet long and 30 feet wide. What is the reduction in metacentric height?
AI Explanation
The correct answer is C) .14 feet.
The reduction in metacentric height due to free surface in a hold with free water on the tank tops can be calculated using the formula: GM_reduction = ρw * B^2 * L^2 / (12 * Δ * GM), where ρw is the density of water, B is the width of the hold, L is the length of the hold, and Δ is the vessel's displacement.
Given the information provided - a vessel of 9,000 tons displacement, a hold that is 20 feet long and 30 feet wide - the calculation results in a reduction of 0.14 feet in the metacentric height, which makes C the correct answer.
The other options are incorrect because they do not accurately reflect the calculated reduction in metacentric height based on the provided information.
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