Question 2537Deck Safety70% to pass
You have approximately 6 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 7 feet? (total displacement is 422 tons)
AI Explanation
The correct answer is D) 0.1 foot.
The shift in the center of gravity after shifting 6 tons of fish 7 feet vertically is 0.1 foot. This is because the total displacement of the vessel is 422 tons, and the weight of the fish being moved (6 tons) is a relatively small fraction of the total displacement. The vertical distance of 7 feet is also relatively small compared to the overall dimensions of the vessel. As a result, the change in the center of gravity is minimal, approximately 0.1 foot.
The other answer choices are incorrect because they either overestimate or underestimate the impact of the weight shift on the center of gravity. Choices A, B, and C do not accurately reflect the small magnitude of the change in the center of gravity for a vessel of this size and displacement.
Related Questions
#2535 Your vessel measures 128 feet long by 21 feet in beam. If the natural rolling period at a draft of 7'-06" is 6 seconds, what is the GM? #2536 Your vessel measures 119 feet long by 17 feet in beam. If the natural rolling period at a draft of 5'-05" is 6 seconds, what is the GM? #2538 You have approximately 15 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 300 tons) #2539 You have approximately 29 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 5 feet? (total displacement is 483 tons) #2540 You have approximately 60 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 960 tons)