Question 2538Deck Safety70% to pass
You have approximately 15 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 300 tons)
AI Explanation
The correct answer is A) 0.4 foot.
The shift in the center of gravity when moving 15 tons of fish from the deck to the fish hold, a vertical distance of 8 feet, can be calculated using the formula: Shift in CG = (Weight Moved x Vertical Distance) / Total Displacement. With a total displacement of 300 tons, moving 15 tons of fish 8 feet vertically results in a shift of 0.4 feet in the center of gravity.
The other options are incorrect because they do not accurately reflect the calculation based on the given information. Options B, C, and D are smaller shifts in the center of gravity than the correct 0.4 foot shift.
Related Questions
#2536 Your vessel measures 119 feet long by 17 feet in beam. If the natural rolling period at a draft of 5'-05" is 6 seconds, what is the GM? #2537 You have approximately 6 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 7 feet? (total displacement is 422 tons) #2539 You have approximately 29 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 5 feet? (total displacement is 483 tons) #2540 You have approximately 60 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 960 tons) #2541 You have approximately 16 tons of fish on deck. What will be the shift in the center of gravity after you shift the fish to the fish hold, a vertical distance of 8 feet? (total displacement is 640 tons)