Question 160Electricity/Electronics - 1st Asst/Chief70% to pass
A 440/110 V single phase transformer supplies a load of 5 kW at 0.8 power factor load. What will be its secondary current ignoring transformer power losses?
AI Explanation
The correct answer is D) 56.82 A.
To calculate the secondary current of the transformer, we need to use the formula: I = P / (V * cos(θ)), where I is the current, P is the power, V is the voltage, and cos(θ) is the power factor.
Given:
- Power (P) = 5 kW = 5,000 W
- Voltage (V) = 110 V (secondary)
- Power factor = 0.8
Plugging these values into the formula, we get:
I = 5,000 W / (110 V * 0.8)
I = 56.82 A
The other options are incorrect because they do not correctly apply the formula to calculate the secondary current of the transformer.
Related Questions
#158 The turn’s ratio of the step-down transformer with dual voltage secondary shown in figure "B" of the illustration is two to one (total). If 220 volts were applied to terminals 'H1' and 'H2', what would be measured across 'X3' and 'X4'? Illustration EL-0082 #159 What is the maximum current allowed to be drawn from the secondary of a 2 kVA step-down transformer with a turn’s ratio of four to one if connected across a 440 volt line? #161 Refer to the simplified schematic of the Ward-Leonard drive system shown in the illustration. The DC winch exhibits normal speed control from minimum to base speed, but the speed cannot be elevated above base speed. What condition would account for this? Illustration EL-0153 #162 Under what circumstance would a hand-held portable phase sequence indicator be used should the main switchboard mounted fixed phase sequence indicator be inoperative? #163 Under what circumstance would a hand-held portable phase sequence indicator be used should the main switchboard mounted fixed phase sequence indicator be inoperative?